Question:
in 25 minutes a man Run 2.40 km on a trade mill facing due east relative to the gym what were his (a) displacement and (b) average velocity this time interval
Answer:
a) The displacement of a man relative to the gym is the displacement of the treadmill itself relative to the gym
Δx=x2−x1=0
since the treadmill is an immovable object.
b) The average velocity is by definition given as
vavg=Δxtotal/Δttotal=0
Since there was no displacement whatsoever.
Not what you are looking for? Go ahead and submit the question, we will get back to you.
