Car is initially at rest = u = 0 m/s

Uniform velocity = v = 5 m/s

Distance = 200m

Time taken is asked

Going by the laws of motion, v = u + at and s = ut + ½ at²

V = u + at

5 = 0 + at

a = 5/t ----------------------(1)

s = ut + ½ at²

200 = 0 + ½ (5/t)t² ---------Substitute a = 5/t

^{200 = 5/2 t implies t = 80 seconds = 1 min 20 seconds}