Question:
a stone of mass m is thrown to a height h. 1) With what minimum velocity should it be thrown? 2)At what height does kinetic energy and potential energy becomes equal? 3)Draw graphically the variation of its kinetic energy and potential energy.?
Answer:
- The minimum velocity is such that the kinetic energy is sufficient for transferring it into potential energy mgh. The minimum v requires a vertical throw of speed is given by 1/2 m v2 = m g h
v = √2 g h - The height at which the kinetic energy is equal to the potential energy is given by m v2 = m g h
h = v2/g
- Graph shows total energy remains the same at any point.
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