Question:
a body projected up with a velocity 'u' to reach a height'h'. to reach double the height,it must be projected up with a velocity of ?
Answer:
if the particle is projected with velocity u then at maximum height its velocity becomes 0
we have ,
V2 = U2 - 2gHmax
U2 = 2gHmax or
U2 directly proportional to Hmax
(Ui)2 / (Uf)2 = (Hmax)i/(Hmax)f
Ui = u , Uf=? , (Hmax)i = h , (Hmax)f = 2h
after substituting these
Uf = (sqrt2)u
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