Question:
a body is projected with a velocity 98m/s the acceleration due to gravity dissapears for 2 seconds then the velocity of end of the next 3 seconds is ?????
Answer:
Velocity after 2sec will be v=u−gt=98−9.8(2)=78.4m/s
As after t=2sec the retardation due to gravity disappear so the velocity will not change further so velocity
at t=3sec will also be 78.4m/s
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