Question:
A police jeep is chasing a culprit going on a motorbike. The motorbike crosses a turning at a speed of 72 km/hr. The jeep follows it at a speed of 90 km/hr, crossing the turning 10 sec later than the bike. Assuming that they travel at constant speeds, how far from the turning will the jeep catch up the bike ?
Answer:
Given,
Speed of culprit= 72 km/hr = 20 m/sec
Speed of police jeep = 90 km/hr =25 m/sec
Let at t=0 the police has reached the turning point. This means culprit has already travelled an extra distance D.
D=20*10+0
=200m
From now let he be caught after time t and covering distance s.
So, S=20t
And the distance covered by police in this t time.
S+200=25t
Dividing these 2 equations we get
S÷(S+200) = 4÷5
So s=800 m or 0.8 km
So its distance from the turning point will be 800+200=1000 m
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