Question:
A particles covers half of its distance with speed v1 and the rest half distance with speed v2 its average speed during the complete journey is ?? Explain in detail with easy calculation plss..
Answer:
Let, the total distance covered by the particle during the complete journey is 2x.
If The half distance (x) covered with the speed v1 in t1 time.
Using formula of speed, v1=x/t1
so, t1= x/v1
And another half distance (x), covered with speed v2 in time t2.
so, v2=x/t2
t2=x/v2
AVERAGE VELOCITY = Total distance /Total time
Total time= t1+t2 = x/v1 + x/v2
=(v2x+v1x)/v1v2
Total distance = x+x=2x
On putting the values of total distance and total time in the formula of average speed, we get
Average speed= 2x /(v2x+v1x / v1v2)
= 2v1v2 /(v1+v2)
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