Question:
A jet aeroplane travelling at the speed of 500 km/h ejects its products of combustion at the
speed of 1500 km/h relative to the jet plane. What is the speed of the latter with respect to an
observer on the ground
Answer:Relative velocity
Relative velocity
VAB=vA−vB
given
VAB=1500Km/h
vA−vB=1500
vA−(−500)=1500
Since the velocity of combustion products and plane are in opposite directions
VA=1000km/h
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