

Ball is thrown vertically upwards, so acceleration is -g.
Given, initial velocity u= 1.4 m/sec
and time t= 2 sec.
So, displacement, S= ut-1/2gt2
S=1.4×2-(1/2)×9.8×22
= 2.8-19.6= -16.8 m
here displacement is negative, which shows that the ball is moving backwards.
The negative displacement shows that the final position of the object (ball in this question) is in the opposite direction of the given velocity.
