Question:
one ball with velocity 50 m/s thrown with angle 45° and range R .If with same velocity another ball is thrown now the range is half what is tha angle now.the answre is sin 1/2 for that what angle is right 15°or 75°.
Answer:
The correct angle in this scenario is 15°.
When a projectile is thrown with a certain velocity and angle, the range (the horizontal distance traveled by the projectile) depends on the initial velocity and the angle of projection. If a second projectile is thrown with the same initial velocity but a different angle, the range will vary.
In this case, you're given that the first ball is thrown with an initial velocity of 50 m/s at an angle of 45° and its range is R.
When the second ball is thrown with the same initial velocity of 50 m/s but with a different angle, and its range is half of R, it means that the range is reduced. To achieve this, the angle must be decreased. The sine function has its maximum value of 1 at 90° and decreases as the angle decreases. To reduce the range to half, you'd need to use an angle where the sine function is equal to 1/2.
The angle whose sine is 1/2 is 30°. However, since the original angle of projection was 45°, the new angle should be 45° - 30° = 15°.
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