Question:
maximum height reached by projectile is 38m the horizontal velocity at that instant is 32m/s find the initial velocity of projection and angle of projection
Answer:
h or distance traveled by object = 38m
v=32m/s
g (gravity)or a(acceleration )=9.8 m/s
we know that v^2-u^2=2as
32- u^2=2×9.8×38
u^2=744.8-32
u^2=712.8
u =26.7m/s
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