

Let the smaller force be B ,the larger force be A,resultant being C.
Given |A| +|B|=18 , |C|=12
A,B,C simply form a right angled triangle with base B vector,hypotenuse being A.
so,you have one equation with you A+B=18
note- ^ is to the power A^2 (A square) A^3 (A cube)
A^2 = B^2+ C^2
A^2 - B^2=C^2
(A-B) (A+B) = 144
(A-B)(18)=144
A-B= 144/18= 8
so simply solve both equations A-B=8
A+B=18
adding both
2A = 26
A= 13
B=5
