Question:
The ceiling of a long hall is 25 m hight. What is the maximum horizontal distance that a ball throw with a speed of 49m/s can go without hitting the ceiling of the wall?
Answer:
The maximum possible height of a projectile-
H = u2 sin2θ/g
Or the angle of projection will be given as-
sinθ = (Hg/u2)1/2
Given, H= 25 m
u= 49 m/sec
Take g= 10 m/sec2
sinθ =[25×10 / (49)2]1/2
= [250/2401]1/2
sinθ = 0.322
θ = sin-1 (0.322)
θ = 18.78o
So, the maximum horizontal range -
R =u2 sin2θ/g
= (49)2 sin(37.56) /10
R= 2401× 0.609 /10
= 146.22 m
Not what you are looking for? Go ahead and submit the question, we will get back to you.
