Question:
Find the direction cosine of vector R = 2i +3j-k
Answer:
If the vector is (x , y, z) and their resultant,
r= mod(x y z)
Then the direction cosines are-
(x/r , y/r ,z/r)
For given vector, R= 2i+3j-k
The resultant r = √(2)2+(3)2+(-1)2
= √14
So,direction cosines = (2/√14 ,3/√14 , -1/√14)
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