Question:
An object is projected at an angle of elevation of 450 with a velocity of 100 m/s. Calculate its
(i) range
(ii) time of flight
Answer:
Given, θ= 45º
Initial velocity u= 100 m/sec
Range R=u²sin2θ/g
=100x100 sin (2x45)/10
=10000 sin90°/10
=10000/10
=1000 m
Time of Flight = T=2usinθ/g
T=2x100x sin 45/10
=2(100)1/√2(10)
=2x10/√2
=2x10x√2/(√2x√2)
=10√2 sec
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