Question:
A wheel of radius 1m rolls forward half a revolition on a horizontal ground. The magnitude of the displacement of the point of the wheel intialy in contact with ground is
Answer:
Consider the figure below -
Assume that after half revolution, the position of the wheel has changed from C1 to C2, which on the plane surface is change from p to P2.
Therefore, PP2 = πr
Also, πr = π metres (As r = 1m)
After half rotation, P will change to P dash,
So, P2Pdash = the diameter of the wheel = 2 metres.
Therefore, PPdash = √(PP2)2 + (P2Pdash)2
So that is, √π2 + 22
That is, π + 4.
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