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Question:
A person standing at point A at t=0 throws a stone with velocity v and at an angle 600 with X axis. Find the co-ordinates of the maximum height reach by the stone
Answer:

According to Newtons second law,

Equation h(t) = −32 for the height h(t).

 Further, the initial velocity and initial position are given by h (0) = v0 and h(0) = 0, respectively.

Our task is to determine the value of v0 that will give a maximum height.

We integrate to get h (t) = −32t + c.

Using the initial velocity, we get v0 = h (0) = −32(0) + c = c. This

If Vo = Cos 60 = 0.5

Then, h (0)= 0.5 cm . The height at this time, the maximum height

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