Question:
A passenger arriving in a new town wishes to go from the station to a hotel located 10 km away on a straight road from the station. A dishonest cabman takes him along a circuitous path 23 km long and reaches the hotel in 28 min. What is (a) the average speed of the taxi, (b) the magnitude of average velocity ? Are the two equal ?
Answer:
(a) Total distance travelled = 23 Km
Total time taken = 28 min
the average speed of the taxi = Total distance travelled/ Total time taken
= 23 x 60/28 = 49.3 Km/h
(b)Distance between the hotel and the station = 10 Km = Displacement of the car
Therefore,
Average velocity = 10 x 60/28 = 21.4 Km/h
Therefore, the two physical quantities are not equal.
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