Question:
A man crosses the river perpendicular to river flow in time t second and travels an equal distance down the stream in T second. The ratio of mans speed in still water to the speed of river water will be...
Answer:
Let velocity of man in still water is v, and water speed with respect to observer on ground be u.
So, velocity of man moving perpendicular will be = √v2-u2
velocity of downstream = v+u
Now according to question,(√v2-u2)t =(v+u)T
So, v/u = t2 +T2 /t2 -T2
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