Question:
A bullet is fired in horizontal direction from the top of a tower 19.6m tall.IIf the bullet fall 500m away from the base of the tower,calculate the velocity of the bullet.
Answer:
Given that the height of the tower = 19.6 m
Horizontal distance covered by the bullet = 500m
We know that v2 – u2 = 2as by the laws of motion.
Since the bullet reaches the ground, the final velocity can be taken as zero. That is v = 0 m/s. Also, we can put g instead of a. By considering the vertical direction of projection, we can say, s = height of the tower = 19.6 m
Hence, v2 – u2 = 2as
0 – u2 = 2 (-9.8) * 19.6
u2 = 384.16
u = √384.16 = 19.6 m/s
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