Question:
A piece of copper having a rectangular cross-section of 15.2 mm x 19.1 mm is pulled in tension with 44,500 N force, producing only elastic deformation. Calculate the resulting strain?
Answer:
Length of the piece of copper (l) = 19.1 mm = 19.1 x 10-3 m
Breadth of the piece of copper ( b) = 15.2 mm = 15.2 x 10-3 m
Area of the copper piece A = l x b = 19.1 x 10-3 x 15.2 x 10-3 = 2.9 x 10-4 m2
Force = 44500 N
Modulus of elasticity of copper (η) = 42 x 109 N/m2
Modulus of elasticity (η) = stress/strain = F/A/Strain
Strain = F/ η = 44500/ 2.9 x 10-4 x 42 x 109 = 3.6 x 10-3
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