Bernoulli Theorem
- For a streamline fluid flow, the sum of the pressure (P), the kinetic energy per unit volume (ρv2/2) and the potential energy per unit volume (ρgh) remain constant.
- Mathematically:- P+ ρv2/2 + ρgh = constant
- where P= pressure ,
- / Volume=1/2mv2/V = 1/2v2(m/V) = 1/2ρv2
- /Volume = mgh/V = (m/V)gh = ρgh

Derive: Bernoulli’s equation
Assumptions:
- Fluid flow through a pipe of varying width.
- Pipe is located at changing heights.
- Fluid is incompressible.
- Flow is laminar.
- No energy is lost due to friction:applicable only to non-viscous fluids.
Mathematically: -
- Consider the fluid initially lying between B and D. In an infinitesimal time interval Δt, this fluid would have moved.
- Suppose v1= speed at B and v2= speed at D, initial distance moved by fluid from to C=v1Δt.
- In the same interval Δtfluid distance moved by D to E = v2Δt.
- P1= Pressureat A1, P2=Pressure at A2.
- Work done on the fluid atleft end (BC) W1 = P1A1(v1Δt).
- Work done by the fluid at the other end (DE)W2 = P2A2(v2Δt)