


Let the mass of the two boxes be m each.
Consider Block 1 and resolve the forces acting on this block.
We find acceleration ma = Tension T in the string; Hence, ma = T -------------Eqn (1)
Consider Block 2 and resolve the forces on this block
F – T = ma ---------------------------Eqn (2)
From (1) substitute T value in Eqn (2)
F –ma = ma
F = 2ma = 2T
Hence, T = F/2 which means tension is half of the force applied to pull the block
