Question:
a car speed have 72km per hour and take time 0.20s and deacliratrion 6miter per second square . what is the distance cover from tghe car
Answer:
Given,
Initial velocity of car, u = 72 km/h = 20 m/sec
Time, t = 0.20 sec
Acceleration, a= -6 m/sec2
Using the second equation of motion,we can find the distance
S=ut+1/2 at2
S=20*0.20 -1/2*6*0.20*0.20
Distance= 3.88 m
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