Question:
a body of mass m is projected with initial speed u at an angle o with the horizontal the change in momentum of body after time t is
Answer:
Considering the angle θ to be 45 degrees,
Max height ,H= v2sin2θ/2g
velocity at max height = ux= vcosθ
angular momentum= muxH
and putting θ =450
angular momentum = mv3/g4√2
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