Question:
A particle of mass m moves with constant speed v on a circular path of radius r. Find magnitude of average force on it in half revolution.
Answer:
Given, particle of mass m is moving with constant velocity v.
(As given that the velocity is constant,but the direction of velocity changes)
As we know,
Change in momentum= Final momentum-initial momentum
= mv-(-mv) =2mv
Average force = change in momentum/ time
Time= Distance/speed
Distance in half revolution= π.r
So,time= π.r/v
Average force= 2mv/(π.r/v)
= 2mv2 /π.r
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