Question:
A parachutist with total weight 75kg drops vertically onto a sandy ground with speed of 2 m/s and comes to a halt over a distance of 0.25m. the average force from the ground on her is close to
Answer:
Using the formula,
v2 = u2 - 2aS,
v = 0, u = 2 m/s,
So, 02 = 22 - 2 x a x 0.25
a = 8 m/s2
So, total acceleration = 10 + 8 = 18 m/s2
Now, force = mass x acceleration,
So, force = 75 x 18
= 1350 N
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