Question:
A car of mass 1500kg is moving with a speed of 12.5m/s on a circular path of radius 20m on a level road . What should be the frictional force between the car and the road so that the car does not slip ? what should be the value of co efficient of friction to attain the force
Answer:
Let μ be the friction coefficient
According to question
f = mv2/r
where, r = friction force, m = mass of car, r = circular trace
We know, f = μN and N = mg
Thus,
μ mg = mv2/r
or, μ = v2/gr where, g = 10 m/s2
or, μ =102/10 x 10 = 1
Now frictional force μN = μ mg = 1 x 1500 x 10 = 15000N
and coefficient of friction 1
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