three identical particles each of mass m are plced on corner of an equilateral triangle of side a the radius of gyration of system about n axis perpendicular to the triangle and passing through one of the corner of triangle
Answer:
The force along the radius of gyration of the system in a direction perpendicular to the triangle is zero. This is because the resultant force from all 3 masses at the radius of gyration will nullify and give a net zero force.
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