Question:
the time of revolution of planet "a" round the sun is 8 times that of another planet "b" .the distance of planet 'a" from sun is how manytimes greater than that of planet "b" from sun
Answer:
Let the time period of planet B be T.
Let the radius of planet A and B be rA and rB respectively.
Time period of A = 8T.
According to Keplers third law,
So, T/8T = rB3/rA3
So, rB3/rA3 = 1/8
rB/rA = 1/2
Thus, rA = 2rB.
Thus, distance of planet A is twice as that of B.
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