


Acceleration due to gravity below the surface of earth
The acceleration due to gravity at a point Q on the surface of the earth is different from the acceleration due to gravity at a point P inside the earth.
As said in the video, consider a point P below the surface of the earth as a distance d. Draw a circle around the point P so that we get the orange sphere as ahown in the diagram.
ρ = Me / (4/3π Re3) ---------------------------------------equation(1)
where
Me = mass of the earth
Volume of sphere= 4/3π Re3
Re = radius of the earth.
Therefore density considering the orange sphere can be written as
ρ = Ms / (4/3π Rs3) ---------------------------equation (2)
Me/Ms = Re3/Rs3 where Rs = (Re-d) 3
d= distance of the body form the centre to the surface of the earth.
Therefore, Me/Ms = Re3/(Re-d)3
Ms = Me(Re-d)3/Re3 ------------------------------equation(3)
Above figure shows the value of g at a depth d. In this case only the smaller sphere of radius (Re–d) contributes to g(d)
F= G m Ms/(Re-d)2
g(d) =F/m where g= acceleration due to gravity at point d below the surface of the earth.
g(d) = GMs/(Re-d)2 --------------------------------------equation (4)
= GMe (Re-d)3/Re3(Re-d)2
=GMe (Re-d)/Re3
Finally, we get
g (d) = g(1-d/Re)
