Question:
sinA/a sinB/b sinc/c equal to k is it true
Answer:
Yes it is true.
sinA/a = sinB/b = sinC/c = k
This can also be written as
a/sinA = b/sinB = c/sinC = k
where A,B,C are the angles of the triangle ABC and a,b,c are the length of the sides of the triangle.
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