Question:
Prove that cot x - cot 2x = cosec 2x
Answer:
Given cot x - cot 2x = cosec 2x
=> cot x = cot 2x + cosec 2x
RHS:
cot 2x + cosec 2x = (cos 2x/sin 2x) + (1/sin 2x)
=> cot 2x + cosec 2x = (cos 2x + 1)/sin 2x {Since cos 2x = 2cos2 x - 1}
=> cot 2x + cosec 2x = (2cos2 x)/(2sin x*cos x)
=> cot 2x + cosec 2x = cos x/sin x
=> cot 2x + cosec 2x = cot x = LHS
Not what you are looking for? Go ahead and submit the question, we will get back to you.
