learnohub
Question:
determine the ratio in which the line 3x + y - 9=0 divides the segment joining the points (1,3) and (2,7)
Answer:

Let the given line divides the line segment joining the points in the ration k : 1 at C

So, by section formula,

Coordinate of C = {(2k + 1)/(k + 1), (7k + 3)/(k + 1)}

This point lies on the line 3x + y - 9 = 0

So, 3(2k + 1)/(k + 1) + (7k + 3)/(k + 1) - 9 = 0

=> 3(2k + 1) + (7k + 3) - 9(k + 1) = 0

=> 6k + 3 + 7k + 3 - 9k - 9 = 0

=> 4k - 3 = 0

=> 4k = 3

=> k = 3/4

So, the required ratios = 3/4 : 1

                               = 3 : 4

Not what you are looking for? Go ahead and submit the question, we will get back to you.

learnohub

Classes

  • Class 6
  • Class 7
  • Class 8
  • Class 9
  • Class 10
  • Class 11
  • Class 12
  • ICSE 6
  • ICSE 7
  • ICSE 8
  • ICSE 9
  • ICSE 10
  • NEET
  • JEE

YouTube Channels

  • LearnoHub Class 11,12
  • LearnoHub Class 9,10
  • LearnoHub Class 6,7,8
  • LearnoHub Kids

Overview

  • FAQs
  • Privacy Policy
  • Terms & Conditions
  • About Us
  • NGO School
  • Contribute
  • Jobs @ LearnoHub
  • Success Stories
© Learnohub 2026.