Question:
ln a group of 50 person,30 like tea,25 like coffee and 16 like both.how many like either tea and coffee
Answer:
Given, n (S) = 50, n (T)=30, n (C)=25, n (T∩C)=16
Thus, n (either tea or coffee) = n (T∪C) = n(T) + n(C) – n(T∩C) = 30+25-16 = 39.
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