Question:
Let A and B be two finites sets such that n(A) = m and n(B) = n. If
the ratio of number of elements of power sets of A and B is 64 and
n(A) + n(B) = 32. Find the value of m and n.
Answer:
Given, n(A) = m and n(B) = n
Again, given the ratio of the number of elements of power sets of A and B is 64
=> 2m /2n = 64
=> 2m-n = 26
=> m - n = 6 .............1
Again, n(A) + n(B) = 32
=> m + n = 32 .........2
Solving eqaion 1 and 2, we get
m = 19 and n = 13
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