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Question:
In a survey of 25 students it was found that 15 had taken Maths, 12 had taken Physics and 11 had taken Chemistry, 5 had taken Maths and chemistry, 9 had taken Maths and Physics, 4 had taken Physics and Chemistry and 3 had taken all the three subjects. Find the number of students that had taken: i) Only Chemistry ii) Only Maths iii) Only Physics iv) Physics and Chemistry but not Maths v) Maths and Physics but not Chemistry vi) Only one of the subject vii) At least one of the subjects viii) None of the subjects
Answer:

Let M: Set of students who have taken Maths

P: Set of students who have taken Physics

C: Set of students who have taken Chemistry

Given,

Total students n(U) = 25

n(M) = 15,  n(P) = 12, n(C) = 11

n(M ∩ C) = 5, n(P ∩ C) = 4, n(M ∩ P) = 9,

n(M ∩ P ∩ C) = 3

1. Number of students taking only Chemistry = n(C - (M ∪ P))

                                                                    = n(C) - n(C ∩ (M ∪ P))

                                                                    = n(C) - [n(C ∩ M) + n(C ∩ P) - n((C ∩ M) ∩ (C ∩ P)) ]

                                                                    = n(C) - n(C ∩ M) - n(C ∩ P) + n(C ∩ M ∩ P)

                                                                    = 11 - 5 - 4 + 3

                                                                    = 14 - 9

                                                                    = 5

2. Number of students taking only Maths = n(M - (P ∪ C))

                                                              = n(M) - n(M ∩ (P ∪ C))

                                                              = n(M) - [n(M ∩ P) + n(M ∩ C) - n((M ∩ P) ∩ (M ∩ C)) ]

                                                              = n(M) - n(M ∩ P) - n(M ∩ C) + n(M ∩ P ∩ C)

                                                              = 15 - 9 - 5 + 3

                                                              = 18 - 14

                                                              = 4

3. Number of students taking only Physics = n(P - (M ∪ C))

                                                             = n(P) - n(P ∩ (M ∪ C))

                                                             = n(P) - [n(P ∩ M) + n(P ∩ C) - n((P ∩ M) ∩ (P ∩ C)) ]

                                                             = n(P) - n(P ∩ M) - n(P ∩ C) + n(P ∩ M ∩ C)

                                                             = 12 - 9 - 4 + 3

                                                             = 15 - 13

                                                             = 2

4. Number of students taking Physics and Chemistry but not Maths = n((P ∩ C) - M)

                                                                                                = n(P ∩ C) - n(P ∩ M ∩ C)

                                                                                                = 4 - 3

                                                                                                = 1

5. Number of students taking Maths and Physics but not Chemistry = n((M ∩ P) - C)

                                                                                                = n(M ∩ P) - n(P ∩ M ∩ C)

                                                                                                = 9 - 3

                                                                                                = 6

6. Number of students taking only one subject = n((only M) + (only P) + (only C))

                                                                   =  n(only M) + n(only P) + n(only C)

                                                                   = 4 + 2 + 5

                                                                   = 11

7. Number of students taking at least one subject = n(M ∪ P ∪ C)

                                                                        = n M) + n(P) + n(C) - n(M ∩ P) - n(P ∩ C) - n(M ∩ C) + n(M ∩ P ∩ C)

                                                                        = 15 + 12 + 11 - 9 - 4 - 5 + 3

                                                                        = 41 - 18

                                                                        = 23

8. Number of students taking none of three subject = 25 -  n(M ∪ P ∪ C)

                                                                          = 25 - 23

                                                                          = 2 

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