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Question:
A G.P. consists of an even number of terms. If the sum of all the terms is 5 times the sum of terms occupying odd places, then find its common ratio.
Answer:

Given that GP consist of even number of terms.

Let number of terms in GP= 2n

Let the GP is: a ,ar2 ,ar3 ,ar4 ,...........ar2n-1 where r is common ratio and a is the first term.

Given that

                  Sum of all terms = 5 * sum of the term occupy at odd place

             => a + ar + ar2 +...........+ ar2n-1 = 5*(a + ar2 + ar4 +........+ ar2n-2

             => a*(1 + r + r2 +.......+ r2n-1 ) = 5*a*( 1 + r2 + r4 +.......+r2n-2 )

             => a* {( r2n -1)/(r-1)} = 5*a* {( (r2 )n -1)/ (r2 -1)}

             => a* {( r2n -1)/(r-1)} = 5*a* {( (r2n -1)/(r -1)*(r+1)}

             => 1 = 5/(r+1)

             => r+1 = 5

             => r = 5-1

             => r = 4

So the common ratio is 4

 

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