

Given
Number of letters = 3
Number of envelope = 3
Total number of ways in which letters put in 3 envelope = 3! = 6
Number of ways in which one letter put in correct envelope = 3 ( Either in 1st envelope or in 2nd envelope or in 3rd envelope )
Number of ways in which two letters or all the 3 letters put in correct envelope = 1
So Total number of ways in which atleast one letter is put in correct envelope = 3+1 = 4
Now the probability that at least one letter is in its proper envelope = 4/6 = 2/3
