Question:
In a certain lottery 10,000 tickets are sold and ten equal prizes are awarded. What is the probability of not getting a prize if you buy (a) one ticket (b) two tickets (c) 10 tickets.
Answer:
Given total number of ticket sold = 10000
Number of equal prices = 10
Now
1. One ticket is bought
Probability of getting a price = 10/10000
Probability of not getting a price = 1- (10/10000) = (10000-10)/10000 = 9990/10000 = 999/1000
2. two ticket are bought
Number of ticket not awarded = 10000-10 = 9990
Probability of not getting a price = 9990C2 / 10000C2
3. 10 tickets are bought
Number of ticket not awarded = 10000-10 = 9990
Probability of not getting a price = 9990C2 / 10000C2
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