Question:
(6) A and B are two mutually exclusive events if P(A) = 0.5 and P(B Ì…)
=0.6.Find P(AUB)
Answer:
Given, A and B are two mutually exclusive events.
So, P(A ∩ B) = 0
Again given P(A) = 0.5 and P(B Ì…) = 0.6
P(B) = 1 - P(B Ì…) = 1 - 0.6 = 0.4
Now, P(A ∪ B) = P(A) + P(B) - P(A ∩ B)
=> P(A ∪ B) = P(A) + P(B)
=> P(A ∪ B) = 0.5 + 0.4 = 0.9
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