Question:
(5) If P(AUB)=0.6 and P(A B)=0.2. Find P(A Ì…) + P(B Ì…)
Answer:
Given, P(AUB) = 0.6 and P(A∩B) = 0.2
Now P(AUB) = P(A) + P(B) - P(A∩B)
=> 0.6 = P(A) + P(B) - 0.2
=> P(A) + P(B) = 0.6 + 0.2
=> P(A) + P(B) = 0.8
=> 1 - P(A Ì…) + 1 - P(B Ì…) = 0.8 {since P(A) + P(A Ì…) = 1}
=> 2 - {P(A Ì…) + P(B Ì…)} = 0.8
=> P(A Ì…) + P(B Ì…) = 2 - 0.8
=> P(A Ì…) + P(B Ì…) = 1.2
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