Question:
(2) Two dice are thrown together. What is the probability that the sum of
the numbers of the two faces is neither 9 nor 11.
Answer:
When two dice are thrown, then total outcome = 36
Sum of 9: {(3, 6), (4, 5), (5, 4), (6, 3)}
Sum of 11: {(5, 6), (6, 5)}
Favourable outcome = 4 + 2 = 6
Now, P(A sum is 9 or 11) = 6/36 = 1/6
So, P(A sum is neither 9 or 11) = 1 - 1/6 = 5/6
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