Question:
(13) Find the probability that in a random arrangement of the letters of the
word “INSTITUTION’ the three T’s are together.
Answer:
Given word: INSTITUTION
Total letters = 11
The word contains 3 I, 2 N, 1 S, 3 T, 1 U and 1 O
Total number of arrangement = 11!/(3!*2!*3!) = 554400
Now, taken 3 T are together.
So total latter = 9
The number of favorable cases = 9!/(3!*2!) = 30240
Now, P(3 T are togather) = 30240/554400 = 0.0545
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