Question:
(10) In a single throw of 3 dice. Find the probability of not getting the same
number on all the dice.
Answer:
When three dice are thrown, then total outcome = 6*6*6 = 216
1. Same number of 3 dice: {(1, 1, 1), (2, 2, 2), (3, 3, 3), (4, 4, 4), (5, 5, 5), (6, 6, 6)}
Favourable outcome = 6
So, P(same number of 3 dice) = 6/216 = 1/36
Now, P(not same number of 3 dice) 1 - 1/36 = 35/36
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