

Find all pairs of concecutive odd natural numbers, both of which are greater than 10, such that their sum is
less than 40
Let x be the odd natural number.
Then the other consecutive odd natural numbers is x + 2
Given that both are greater than 10
=> x > 10 and x + 2 > 10
=> x > 10 and x > 10 - 2
=> x > 10 and x > 8
=> x > 10 ..........1
Again given that their sum is less than 40
=> x + x + 2 < 40
=> 2x + 2 < 40
=> 2x < 40 - 2
=> 2x < 38
=> x < 38/2
=> x < 19 ...........2
From equation 1 and 2, we get
x > 10 and x < 19
Since x is an odd number
So, x = 11, 13, 15, 17
Since, their sum is less than 40
Hence, the required pairs of odd natural numbers are (11, 13), (13, 15), (15, 17), (17, 19)
