Question:
Find the derivative of the following functions: cosec x cot x
Answer:
let y = cosecx *cotx
=> y =(1/sinx) * (cosx/sinx)
=> y = cosx/sin2 x
Now dy/dx = {sin2 x(-sinx) - cosx*2*sinx*cosx}/sin4 x
= (-sin3 x - 2sinx * cos2 x)/sin4 x
= -1/sinx - 2*cos2 x/sin3 x
= -cosecx - 2* cot2 x*cosecx
Not what you are looking for? Go ahead and submit the question, we will get back to you.
