Question:
Find the derivative of the following functions: (ax + b)/(cx + d )2
Answer:
Let y = (ax + b)/(cx + d )2
then dy/dx = {(cx + d)2 *a - (ax + b)*2*(cx+d)c}/(cx + d)4
= (cx+d)*{a(cx+d) - 2c(ax+b)}/(cx + d)4
= {a(cx+d) - 2c(ax+b)}/(cx + d)3
= (acx + ad - 2acx - 2bc)/(cx + d)3
= (ad -acx - 2bc)/(cx + d)3
So derivative of (ax + b)/(cx + d )2 = (ad -acx - 2bc)/(cx + d)3
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