

Let y = ( a + b sinx)/(c+d cosx)
=> dy/dx = {(c+d cosx)*(b cosx) - (a + b sinx)(-d sinx)}/(c + d cosx)2
= (bc *cosx + bd *cos2 x + ad *sinx +bd sin2 x)/(c + d cosx)2
= {bc *cosx + ad *sinx + bd*(cos2 x + sin2 x)}/(c +d cosx)2
= {bc *cosx + ad *sinx + bd)}/(c +d cosx)2
So derivative of ( a + b sinx)/(c+d cosx) = {bc *cosx + ad *sinx + bd)}/(c +d cosx)2
