Question:
Find the derivative of the following functions: (Secx-1) /(Secx+1)
Answer:
Given (Secx-1) /(Secx+1)
= {(1/cosx)-1)} /{(1/cosx)+1)}
= (1-cosx)/(1+cosx)
Let y = (1-cosx)/(1+cosx)
=> dy/dx = {(1+cosx)*(sinx) - (1-cosx)(-sinx)}/(1+cosx)2
= (sinx + sinx*cosx + sinx - sinx*cosx)/(1+cosx)2
= (2*sinx)/(1+cosx)2
So derivative of {(Secx-1) /(Secx+1)} = = (2*sinx)/(1+cosx)2
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